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IBM C1000-112 Exam Syllabus Topics:
| Section | Objectives |
|---|---|
| Topic 1: Quantum Gates and Circuits | - Quantum circuit construction - Single-qubit gates (X, Y, Z, H) - Multi-qubit gates (CNOT, controlled operations) |
| Topic 2: Qiskit Programming | - Qiskit Terra basics - Simulators and Aer backend usage - Building and executing circuits |
| Topic 3: Noise and Real Hardware | - IBM Quantum hardware execution - Quantum noise and error sources |
| Topic 4: Quantum Computing Fundamentals | - Superposition and entanglement - Qubits and quantum states - Measurement and collapse |
| Topic 5: Quantum Algorithms | - Grover's search algorithm - Basic algorithmic complexity concepts - Deutsch-Jozsa algorithm |
IBM Fundamentals of Quantum Computation Using Qiskit v0.2X Developer Sample Questions:
How does the concept of "quantum superposition" contribute to information processing in quantum systems?
- A. It ensures deterministic outcomes in quantum computations
- B. It enables the simultaneous representation of multiple states
- C. It limits the capacity for storing information in qubits
- D. It allows for the storage of classical bits in quantum systems
Correct Answer: B 🗳️
What is the primary advantage of quantum information processing over classical information processing?
- A. Classical information can hold more data than quantum information
- B. Classical information is more secure than quantum information
- C. Quantum information is always error-free
- D. Quantum information enables parallel processing and superposition
Correct Answer: D 🗳️
Predict the state vector output of the below quantum circuit?
qc= QuantumCircuit(3)
qc.h(0)
qc.z(0)
qc.x(1)
qc.cx(0,1)
qc.x(2)
qc.cx(1,2)
backend_sv = BasicAer.get_backend('statevector_simulator')
job = execute(qc, backend_sv,shots=1024)
result = job.result()
sv_ev = result.get_statevector(qc)
- A.
- B.
- C.
- D.
Correct Answer: C 🗳️
Which quantum gate is commonly used for reversing a quantum operation?
- A. CNOT gate
- B. Pauli-X gate
- C. T gate
- D. Hadamard gate
Correct Answer: B 🗳️
What would be the fidelity result(s) for these two operators, which differ only by global phase?
op_a = Operator(XGate())
op_b = numpy.exp(1j * 0.5) * Operator(XGate())
- A. state_fidelity() of 1.0
- B. state_fidelity() and average_gate_fidelity() of 1.0
- C. state_fidelity(), average_gate_fidelity() and process_fidelity() of 1.0
- D. average_gate_fidelity() and process_fidelity() of 1.0
Correct Answer: D 🗳️
